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SQL union ALL用法

2024-11-07 来源:个人技术集锦

union all 操作符用于合并两个或多个 SELECT 语句的结果集,并且不做去重操作。

可能这样讲比较抽象,以一道题为例子:

描述

题目:现在运营想要分别查看学校为山东大学或者性别为男性的用户的device_id、gender、age和gpa数据,请取出相应结果,结果不去重。

示例:user_profile

iddevice_idgenderageuniversitygpaactive_days_within_30question_cntanswer_cnt
12138male21北京大学3.47212
23214male复旦大学415525
36543female20北京大学3.212330
42315female23浙江大学3.6512
55432male25山东大学3.8201570
62131male28山东大学3.315713
74321male26复旦大学3.69652

根据示例,你的查询应返回以下结果(注意输出的顺序,先输出学校为山东大学再输出性别为男生的信息):

device_idgenderagegpa
5432male253.8
2131male283.3
2138male213.4
3214maleNone4
5432male253.8
2131male283.3
4321male283.6

示例1

输入:

drop table if exists `user_profile`;
drop table if  exists `question_practice_detail`;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`gpa` float,
`active_days_within_30` int ,
`question_cnt` int ,
`answer_cnt` int 
);
CREATE TABLE `question_practice_detail` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`question_id`int NOT NULL,
`result` varchar(32) NOT NULL
);
CREATE TABLE `question_detail` (
`id` int NOT NULL,
`question_id`int NOT NULL,
`difficult_level` varchar(32) NOT NULL
);

INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学',3.4,7,2,12);
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学',4.0,15,5,25);
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学',3.2,12,3,30);
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学',3.6,5,1,2);
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学',3.8,20,15,70);
INSERT INTO user_profile VALUES(6,2131,'male',28,'山东大学',3.3,15,7,13);
INSERT INTO user_profile VALUES(7,4321,'male',28,'复旦大学',3.6,9,6,52);
INSERT INTO question_practice_detail VALUES(1,2138,111,'wrong');
INSERT INTO question_practice_detail VALUES(2,3214,112,'wrong');
INSERT INTO question_practice_detail VALUES(3,3214,113,'wrong');
INSERT INTO question_practice_detail VALUES(4,6543,111,'right');
INSERT INTO question_practice_detail VALUES(5,2315,115,'right');
INSERT INTO question_practice_detail VALUES(6,2315,116,'right');
INSERT INTO question_practice_detail VALUES(7,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(8,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(9,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(10,2131,113,'right');
INSERT INTO question_practice_detail VALUES(11,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(12,2315,115,'right');
INSERT INTO question_practice_detail VALUES(13,2315,116,'right');
INSERT INTO question_practice_detail VALUES(14,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(15,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(16,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(17,2131,113,'right');
INSERT INTO question_practice_detail VALUES(18,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(19,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(20,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(21,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(22,2131,113,'right');
INSERT INTO question_practice_detail VALUES(23,5432,113,'wrong');
INSERT INTO question_detail VALUES(1,111,'hard');
INSERT INTO question_detail VALUES(2,112,'medium');
INSERT INTO question_detail VALUES(3,113,'easy');
INSERT INTO question_detail VALUES(4,115,'easy');
INSERT INTO question_detail VALUES(5,116,'medium');
INSERT INTO question_detail VALUES(6,117,'easy');

复制输出:

5432|male|25|3.8
2131|male|28|3.3
2138|male|21|3.4
3214|male|None|4.0
5432|male|25|3.8
2131|male|28|3.3
4321|male|28|3.6

解题思路 一:

但总会存在一个人满足了两个条件只筛选一次。这里的坑时使用or,因为or自带去重,而union等价于or,但union all 可以不去重,所以本体考察or与union的细节使用

SELECT distinct up.device_id,up.gender,up.age,up.gpa,up.university FROM user_profile up
LEFT JOIN question_practice_detail qd ON up.device_id= qd.device_id
 WHERE up.university = "山东大学" OR up.gender = "male"
 ORDER BY up.university desc,up.gender desc

上面方法错误:

解题思路 二:

使用UNION ALL 把两个表链接起来 利用UNION ALL去方式粘贴两个表完成题目中的默认排序,并且题目中提到的可以重复,则不去重

select device_id , gender , age , gpa from user_profile where university = '山东大学' 
UNION ALL
select device_id , gender , age , gpa from user_profile where gender = 'male'

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